Question

question 9 (1 point)
a 15.0-kg object is moved from a height of 7.00 m above a floor to a height of 13.0
m above the floor. what is the change in gravitational potential energy?
882 j
1910 j
zero
1030 j

Explanation:

Step1: Recall the formula for gravitational potential energy change

The formula for the change in gravitational potential energy ($\Delta PE$) is $\Delta PE = mg\Delta h$, where $m$ is the mass, $g$ is the acceleration due to gravity (we use $g = 9.8\ m/s^2$), and $\Delta h$ is the change in height.

Step2: Calculate the change in height

The initial height $h_1 = 7.00\ m$ and the final height $h_2 = 13.0\ m$. So, $\Delta h = h_2 - h_1 = 13.0 - 7.00 = 6.00\ m$.

Step3: Substitute values into the formula

We know $m = 15.0\ kg$, $g = 9.8\ m/s^2$, and $\Delta h = 6.00\ m$. Plugging these into the formula: $\Delta PE = 15.0 \times 9.8 \times 6.00$.

First, calculate $15.0 \times 9.8 = 147$. Then, $147 \times 6.00 = 882\ J$.

Answer:

882 J