Question

question 9
if galaxy a is four times more distant than galaxy b, then according to hubbles law, galaxy a will recede ____________ times faster than galaxy b. 2 pts

Explanation:

Step1: State Hubble's Law

Hubble's Law is $v = H_0 d$, where $v$ = recession velocity, $H_0$ = Hubble constant, $d$ = distance.

Step2: Define distances for galaxies

Let $d_B$ = distance of galaxy B. Then $d_A = 4d_B$.

Step3: Calculate velocities

$v_B = H_0 d_B$, $v_A = H_0 (4d_B) = 4H_0 d_B$.

Step4: Find velocity ratio

$\frac{v_A}{v_B} = \frac{4H_0 d_B}{H_0 d_B} = 4$.

Answer:

4