Question

question 42
(problem reference m.5)
a projectile is fired horizontally with an initial speed of 50.0 m/s. it strikes the ground 3.00 s later. neglect air resistance.
what is the magnitude of the horizontal displacement of the projectile?
150 m
225 m
450 m
29 m
75 m

Explanation:

Step1: Recall the formula for horizontal displacement

For projectile motion with no air resistance, the horizontal displacement \(x = v_{0x}t\), where \(v_{0x}\) is the initial horizontal velocity and \(t\) is the time of flight.

Step2: Substitute the given values

Given \(v_{0x}=50.0\ m/s\) and \(t = 3.00\ s\). Then \(x=(50.0\ m/s)\times(3.00\ s)\)

$$x = 150\ m$$

Answer:

150 m