Question

question 25
identify each factor of,
$9x^2 - 49$
$\square$ $3x+7$
$\square$ $9x+7$
$\square$ $3x-7$
$\square$ $9x-7$

Explanation:

Step1: Recognize the formula

The expression \(9x^2 - 49\) is a difference of squares, which follows the formula \(a^2 - b^2=(a + b)(a - b)\).
Here, \(a = 3x\) (since \((3x)^2=9x^2\)) and \(b = 7\) (since \(7^2 = 49\)).

Step2: Apply the formula

Using the difference of squares formula, we factor \(9x^2-49\) as \((3x + 7)(3x - 7)\).

Step3: Identify the factors

From the factored form \((3x + 7)(3x - 7)\), we can see that the factors are \(3x + 7\) and \(3x - 7\).

Answer:

A. \(3x + 7\), C. \(3x - 7\)