Question

question 7 of 25
a box of mass 115 kg sits on an inclined surface with an angle of 59°. what is the component of the weight of the box along the surface?

a. 966 n
b. 581 n
c. 619 n
d. 1127 n

Explanation:

Step1: Calculate the weight of the box

The weight of an object is given by $W = mg$, where $m = 115$ kg and $g= 9.8$ m/s². So $W=115\times9.8 = 1127$ N.

Step2: Find the component of weight along the inclined - surface

The component of the weight along the inclined surface is $W_{parallel}=W\sin\theta$, where $\theta = 59^{\circ}$ and $W = 1127$ N. So $W_{parallel}=1127\times\sin(59^{\circ})\approx1127\times0.857 = 966$ N.

Answer:

A. 966 N