Question

question 23
2 pts
given the following phenotypic reactions, determine which of the following genotypes is possible.

anti-d anti-c anti-e anti-c anti-e
0 + 0 + +

• r2r
• r

\

• rr
• rzr

Explanation:

Determine the antigen phenotype

Using the Rh Blood Group System knowledge point

• Anti-D: \(0\) (D-negative)
• Anti-C: \(+\) (C-positive)
• Anti-E: \(0\) (E-negative)
• Anti-c: \(+\) (c-positive)
• Anti-e: \(+\) (e-positive)
• The phenotype is: D-, C+, E-, c+, e+

Translate Wiener nomenclature to Fisher-Race

Using the Wiener Nomenclature knowledge point

• \(R_2r\): \(DcE/dce\) (D-positive, contains E)
• \(r''r''\): \(dcE/dcE\) (C-negative, contains E)
• \(r'r\): \(dCe/dce\) (D-negative, contains C, c, e)
• \(R_zr\): \(DCE/dce\) (D-positive, contains E)

Match genotypes to the observed phenotype

Using the Rh Blood Group System and Wiener Nomenclature knowledge points

• Target phenotype: D-negative, C-positive, E-negative, c-positive, e-positive.
• \(R_2r\) and \(R_zr\) are D-positive (\(0\) reaction with Anti-D is expected for D-negative).
• \(r''r''\) is C-negative and E-positive (expected Anti-C: \(0\), Anti-E: \(+\)).
• \(r'r\) (\(dCe/dce\)) produces antigens C, c, and e, while lacking D and E. This perfectly matches the reactions: Anti-D (\(0\)), Anti-C (\(+\)), Anti-E (\(0\)), Anti-c (\(+\)), Anti-e (\(+\)).

Answer:

• (A) R2r
• (B) r"r"
• (C) r'r (Correct answer)
• (D) Rzr