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Question
question 19 (mandatory) (1 point) which coordinate is the vertex of the function $f(x) = -4(x - 3)^2 - 9$ a) (3, 9) b) (9, -3) c) (3, -9) d) (12, -9)
Step1: Recall vertex form of parabola
The vertex form of a quadratic function is \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.
Step2: Identify \(h\) and \(k\) from given function
Given the function \( f(x) = -4(x - 3)^2 - 9 \), we compare it with the vertex form. Here, \( h = 3 \) and \( k = -9 \). So the vertex is \((h, k)=(3, -9)\).
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c) (3, -9)