Question

question 16 (1 point)
an old lady rolls down a hill at 3 meters/second. the hill is 36 meters long. how many
seconds does it take the old lady to reach the bottom of the hill?
a) 39 seconds b) 12 seconds
c) 15 seconds d) 33 seconds
a
b
c
d
question 17 (1 point)
an object accelerates at a rate of 1.2 m/s² w for 2.0 s and has an initial velocity of
5.0 m/s e. what is its final velocity?
(a) 1.4 m/s e (b) 2.6 m/s e
(c) 6.2 m/s w (d) 7.4 m/s w
a
b
c
d

Explanation:

Question 16

Step1: Recall the formula for time

The formula for time \(t\) when given distance \(d\) and speed \(v\) is \(t=\frac{d}{v}\).

Step2: Substitute the values

Here, \(d = 36\) meters and \(v=3\) meters/second. So \(t=\frac{36}{3}\).

Step3: Calculate the value

\(\frac{36}{3}=12\)

Step1: Recall the formula for final velocity

The formula for final velocity \(v_f\) is \(v_f=v_i + at\), where \(v_i\) is the initial velocity, \(a\) is the acceleration and \(t\) is the time.

Step2: Substitute the values

Given \(v_i = 5.0\) m/s, \(a = 1.2\) m/s² and \(t = 2.0\) s. Then \(v_f=5.0+1.2\times2.0\).

Step3: Calculate the value

First, calculate \(1.2\times2.0 = 2.4\). Then \(v_f=5.0 + 2.4=7.4\) m/s

Answer:

B. 12 seconds

Question 17