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question 14 of 29
a climber is attached to a vertical rope that has a tension of 789 n. if the climber has a mass of 85 kg, what is the net force on the climber?
a: 789 n down
b: 842 n up
c: 48 n down
d: 48 n up
Step1: Calculate the weight of the climber
The weight formula is $F = mg$, where $m = 85\ kg$ and $g=9.8\ m/s^{2}$. So $F = 85\times9.8=833\ N$ (down - ward).
Step2: Analyze the tension force
The tension in the rope is $T = 785\ N$ (up - ward).
Step3: Calculate the net force
The net force $F_{net}=F - T$. Substitute the values: $F_{net}=833 - 785 = 48\ N$. Since the weight is greater than the tension, the net force is downward.
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C. 48 N down