Question

question 11 (1 point)
calculate these 3 cars speeds, then rank them in order of fastest to slowest, with 3 being the fastest car and 1 the slowest car.
car a - distance: 4 meters, time: 2 sec
car b - distance: 2 meters, time: 2 sec
car c - distance: 8 meters, time: 2 sec
a) car a = 1
car b = 2
car c = 3
b) car a = 2
car b = 1
car c = 3
c) car a = 3
car b = 1
car c = 2
d) car a = 3
car b = 2
car c = 1

Explanation:

Step1: Calculate speed of Car A

Speed formula: \(v=\frac{d}{t}\). For Car A, \(d = 4\) meters, \(t=2\) sec. So \(v_A=\frac{4}{2}=2\) m/s.

Step2: Calculate speed of Car B

For Car B, \(d = 2\) meters, \(t = 2\) sec. So \(v_B=\frac{2}{2}=1\) m/s.

Step3: Calculate speed of Car C

For Car C, \(d = 8\) meters, \(t = 2\) sec. So \(v_C=\frac{8}{2}=4\) m/s.

Step4: Rank the cars

Since \(v_C>v_A>v_B\), ranking (3 - fastest, 1 - slowest): Car C = 3, Car A = 2, Car B = 1.

Answer:

B. Car A = 2, Car B = 1, Car C = 3