Question

question 5 of 10 how long is the minor axis for the ellipse shown below?
\\(\frac{(x + 3)^2}{64}+\frac{(y - 7)^2}{4}=1\\)
a. 8
b. 16
c. 64
d. 4

Explanation:

Step1: Recall ellipse standard - form

The standard form of an ellipse is $\frac{(x - h)^2}{a^2}+\frac{(y - k)^2}{b^2}=1$. For $\frac{(x + 3)^2}{64}+\frac{(y - 7)^2}{4}=1$, we have $a^2 = 64$ and $b^2 = 4$.

Step2: Determine the semi - minor axis

Since $b^2 = 4$, then $b=\sqrt{4}=2$. The length of the minor axis is $2b$.

Step3: Calculate the length of the minor axis

$2b=2\times2 = 4$.

Answer:

D. 4