Question

in △pqr, sin r = $\frac{3}{5}$. what is cos p?

Explanation:

Step1: Recall trigonometric - angle relationship

In a right - triangle $\triangle PQR$ with $\angle Q = 90^{\circ}$, $\angle P+\angle R=90^{\circ}$.

Step2: Use co - function identity

We know the co - function identity[SSE Completed, Client Connection Error][SSE Completed, Client Connection Error][LLM SSE On Failure]

Answer:

D. $\frac{3}{5}$