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the population of bacteria in an experiment increases by 73% every 2 da…

Question

the population of bacteria in an experiment increases by 73% every 2 days. if there were 150 bacteria microorganisms at the beginning, how many would there be after 8 days?
future amount = ?(1 + )
future amount = 1(1 + r)^t
enter the number that belongs in the green box.

Explanation:

Step1: Identify the initial amount

The initial number of bacteria is 150, which is the value that goes in the green - box in the compound - growth formula.

Step2: Identify the growth rate and time intervals

The growth rate $r = 0.73$ (since 73% = 0.73) and the time period is 2 days. In 8 days, the number of 2 - day intervals $t=\frac{8}{2}=4$.

Step3: Calculate the future amount

Using the formula $Future\ Amount = P(1 + r)^t$, where $P = 150$, $r=0.73$, and $t = 4$. But we are only asked for the value in the green box which is the initial amount $P$.

Answer:

150