Question

a piece of lead with a mass of 623 g has a heat capacity of 78.5 j/°c. what is the specific heat of lead?

Explanation:

Step1: Recall the formula for specific heat

The formula for specific heat \( c=\frac{C}{m} \), where \( C \) is the heat capacity and \( m \) is the mass.

Step2: Substitute the given values into the formula

Given \( C = 78.5\ J/^{\circ}C \) and \( m=623\ g \). Then \( c=\frac{78.5\ J/^{\circ}C}{623\ g} \).

Step3: Calculate the value

\( c=\frac{78.5}{623}\approx0.126\ J/g^{\circ}C \)

Answer:

0.126 J/g °C