Question

perform the indicated operation.
$(4x^3 - 8x^2 + 8x - 6) - (8x^3 - 4x^2 - 6x + 7)$

write the polynomial in standard form.
$(4x^3 - 8x^2 + 8x - 6) - (8x^3 - 4x^2 - 6x + 7) = \square$

Explanation:

Step1: Distribute the negative sign

$(4x^3 - 8x^2 + 8x - 6) - 8x^3 + 4x^2 + 6x - 7$

Step2: Combine like $x^3$ terms

$4x^3 - 8x^3 = -4x^3$

Step3: Combine like $x^2$ terms

$-8x^2 + 4x^2 = -4x^2$

Step4: Combine like $x$ terms

$8x + 6x = 14x$

Step5: Combine constant terms

$-6 - 7 = -13$

Step6: Assemble standard form

$-4x^3 - 4x^2 + 14x - 13$

Answer:

$-4x^3 - 4x^2 + 14x - 13$