Question

perform the following operation and express in simplest form. \\(\frac{x^2 + 8x - 9}{x - 1} \cdot \frac{4x^2}{x^2 + x - 72}\\)

Explanation:

Step1: Factor all polynomials

$\frac{(x+9)(x-1)}{x-1} \cdot \frac{4x^2}{(x+9)(x-8)}$

Step2: Cancel common factors

Cancel $(x-1)$ and $(x+9)$ from numerator and denominator:
$\frac{4x^2}{x-8}$

Answer:

$\frac{4x^2}{x-8}$