Question

2.

perform all operations. give the answer in \\(a + bi\\) form.

\\-2i(3 - 8i)\\

Explanation:

Distribute the term outside the parentheses

$$ -2i(3 - 8i) = -2i(3) - (-2i)(8i) = -6i + 16i^2 $$

Substitute the value of the imaginary unit squared

$$ i^2 = -1 \implies -6i + 16(-1) = -6i - 16 $$

Rearrange into standard complex form

$$ -16 - 6i $$

Answer:

Perform all operations. Give the answer in \(a + bi\) form.

$$-2i(3 - 8i)$$

<blank>\(-16 - 6i\)</blank>