Question

1. a paper airplane is thrown with an initial velocity of 2.4 m/s and an angle of 60°. find the ( v_{oy} ).

2.08 m/s
1.70 m/s
1.2 m/s
2.32 m/s

Explanation:

Step1: Decompose the initial velocity

The vertical component of the initial velocity \(v_{0y}\) can be found using the formula \(v_{0y}=v_0\sin\theta\), where \(v_0 = 2.4\space m/s\) and \(\theta = 60^{\circ}\).

Step2: Calculate \(v_{0y}\)

We know that \(\sin60^{\circ}=\frac{\sqrt{3}}{2}\approx0.866\). Then \(v_{0y}=2.4\times\sin60^{\circ}\).

$$v_{0y}=2.4\times0.866 = 2.0784\approx2.08\space m/s$$

Answer:

2.08 m/s