Question

one of these representations is not like the others. tap on the one that doesnt belong. \the projectile has a zero velocity at the highest location.\

Explanation:

Step1: Analyze projectile motion properties

In projectile motion, the horizontal component of velocity ($v_x$) remains constant (assuming no air - resistance), and the vertical component of velocity ($v_y$) changes due to gravity. At the highest point of the projectile's trajectory, the vertical component of velocity ($v_y = 0$), but the horizontal component of velocity ($v_x
eq0$). The acceleration in projectile motion is constant (equal to the acceleration due to gravity, $g = 9.8\ m/s^{2}$) and acts vertically downwards throughout the motion.

Step2: Examine each representation

• Text representation: "The projectile has a zero velocity at the highest location" is incorrect. As we know from projectile motion, at the highest point, $v_y = 0$, but $v_x

eq0$, so the total velocity $v=\sqrt{v_x^{2}+v_y^{2}}
eq0$.

• Acceleration - vector diagram: The arrows (acceleration vectors) are all of the same length (constant magnitude, since $a = g$ is constant) and point downwards, which is correct for projectile motion.
• Velocity - vector diagram: If we assume the horizontal arrows represent $v_x$ (constant) and the vertical arrows represent $v_y$ (changing, with a zero - length vertical arrow at the appropriate point for the highest location, if we consider the correct velocity components), but the text is wrong.
• Table: The table shows that $v_x$ is constant ($v_x=33.9\ m/s$) and $v_y$ changes ($v_y = 0$ at $t = 2.0\ s$ which is the time to reach the highest point if we use $v_y=v_{0y}-gt$ and $v_{0y}=19.6\ m/s$, $g = 9.8\ m/s^{2}$, $t=\frac{v_{0y}}{g}=\frac{19.6}{9.8}=2\ s$). This is a correct representation of projectile motion velocity components.

Answer:

The text “The projectile has a zero velocity at the highest location”