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Question
an object with a mass of 6.0 kg and an acceleration of 1.2 m/s² has a net force of n acting on it. (to two significant digits)
Step1: Recall Newton's second law
Newton's second law is \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration.
Step2: Substitute the given values
Given \(m = 6.0\space kg\) and \(a=1.2\space m/s^{2}\). Substitute into the formula: \(F=(6.0)(1.2)\).
Step3: Calculate the result
\(F = 7.2\space N\)
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\(7.2\)