Question

h= normal blood clotting
h=hemophilia
x^h x^h x x^h y
what is the probability that any of their offspring will have hemophilia?
4/4 1/4 2/4 3/4

Explanation:

Step1: Create Punnett Square

For the cross \(X^H X^h \times X^H Y\), the possible gametes from the female (\(X^H X^h\)) are \(X^H\) and \(X^h\). From the male (\(X^H Y\)) are \(X^H\) and \(Y\). The Punnett square is:

	\(X^H\)	\(Y\)
\(X^h\)	\(X^H X^h\)	\(X^h Y\)

Step2: Identify Hemophilic Offspring

Hemophilia is \(X^h Y\) (since males with \(X^h\) and females need \(X^h X^h\), but here female gametes have one \(h\)). From the square, only \(X^h Y\) has hemophilia. Total offspring genotypes: 4. Hemophilic: 1 (\(X^h Y\)).

Step3: Calculate Probability

Probability = \(\frac{\text{Number of hemophilic offspring}}{\text{Total offspring}} = \frac{1}{4}\).

Answer:

1/4