Question

non-mendelian inheritance
assignment
active
practicing using punnett squares
a chicken with black feathers (bb) is crossed with
a chicken with white feathers (ww). the offspring
have black and white feathers.
what is the genotype of the offspring?

1. → bw
2. → bw
3. → bw
4. → bw

complete
this is because there
are two
done
incomplete dominance
codominance

Explanation:

Step1: Analyze the Punnett square

The parent genotypes are \( BB \) (black - feathered chicken) and \( WW \) (white - feathered chicken). In a Punnett square, when we cross \( BB\times WW \), each parent contributes one allele. The possible combinations are \( BW \) for each of the four offspring in the Punnett square.

Step2: Recall the concepts of non - Mendelian inheritance

• In incomplete dominance, the heterozygous phenotype is an intermediate of the two homozygous phenotypes.
• In codominance, both alleles are expressed simultaneously in the heterozygous phenotype. Here, the offspring have both black and white feathers, which is a case of codominance.

Answer:

The genotype of the offspring is \( BW \). This is codominance because both the \( B \) (black) and \( W \) (white) alleles are expressed simultaneously in the phenotype of the offspring.