QUESTION IMAGE
Question
name: nayeliz dejesus
date: 9/10
bell:
unit 2: logic & proof
homework 7: segment proofs
this is a 2 - page document!
use the segment addition postulate to write three equations using the diagram below.
1.
2.
3.
diagram: p---q---r---s---t
complete the proofs below by filling in the missing statements and reasons
- given: x is the midpoint of (overline{wy}), (overline{wx} cong overline{xz})
prove: (overline{xy} cong overline{xz})
diagram: w---x---y, z above x
statements | reasons
- x is the midpoint of (overline{wy}) | 1.
- wx = xy | 2.
- (overline{wx} cong overline{xz}) | 3.
- wx = xz | 4.
- xy = xz | 5.
- (overline{xy} cong overline{xz}) | 6.
- given: (overline{ab} cong overline{cd})
prove: (overline{ac} cong overline{bd})
diagram: a---b---c---d
statements | reasons
- (overline{ab} cong overline{cd}) | 1.
- ab = cd | 2.
- ac + cd = ad | 3.
- ab + bd = ad | 4.
- cd + bd = ad | 5.
- ac + cd = cd + bd | 6.
- ac = bd | 7.
- (overline{ac} cong overline{bd}) | 8.
© gina wilson (all things algebra), 2014
Problem 1: Using Segment Addition Postulate
The diagram has points \( P, Q, R, S, T \) in order. The segment addition postulate states that if three points are collinear, the sum of the lengths of the two smaller segments equals the length of the larger segment.
Step 1: Equation with \( P, Q, R \)
If \( Q \) is between \( P \) and \( R \), then \( PQ + QR = PR \).
Step 2: Equation with \( Q, R, S \)
If \( R \) is between \( Q \) and \( S \), then \( QR + RS = QS \).
Step 3: Equation with \( R, S, T \)
If \( S \) is between \( R \) and \( T \), then \( RS + ST = RT \).
Problem 4: Proof (Midpoint and Congruence)
Given: \( X \) is the midpoint of \( \overline{WY} \), \( \overline{WX} \cong \overline{XZ} \)
Prove: \( \overline{XY} \cong \overline{XZ} \)
| Statements | Reasons |
|---|---|
| 2. \( WX = XY \) | 2. Definition of midpoint (a midpoint divides a segment into two equal parts) |
| 3. \( \overline{WX} \cong \overline{XZ} \) | 3. Given |
| 4. \( WX = XZ \) | 4. Definition of congruent segments (congruent segments have equal length) |
| 5. \( XY = XZ \) | 5. Substitution Property (replace \( WX \) with \( XY \) from Step 2) |
| 6. \( \overline{XY} \cong \overline{XZ} \) | 6. Definition of congruent segments (if lengths are equal, segments are congruent) |
Problem 5: Proof (Congruent Segments)
Given: \( \overline{AB} \cong \overline{CD} \)
Prove: \( \overline{AC} \cong \overline{BD} \)
| Statements | Reasons |
|---|---|
| 2. \( AB = CD \) | 2. Definition of congruent segments |
| 3. \( AC + CD = AD \) | 3. Segment Addition Postulate ( \( C \) is between \( A \) and \( D \), so \( AC + CD = AD \)) |
| 4. \( AB + BD = AD \) | 4. Segment Addition Postulate ( \( B \) is between \( A \) and \( D \), so \( AB + BD = AD \)) |
| 5. \( CD + BD = AD \) | 5. Substitution Property (replace \( AB \) with \( CD \) from Step 2) |
| 6. \( AC + CD = CD + BD \) | 6. Transitive Property (both equal \( AD \), so they equal each other) |
| 7. \( AC = BD \) | 7. Subtraction Property (subtract \( CD \) from both sides) |
| 8. \( \overline{AC} \cong \overline{BD} \) | 8. Definition of congruent segments |
Final Answers (Key Equations/Proof Steps)
- \( PQ + QR = PR \)
- \( QR + RS = QS \)
- \( RS + ST = RT \)
(For Proofs 4 and 5, the completed tables above show the full reasoning.)
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Problem 1: Using Segment Addition Postulate
The diagram has points \( P, Q, R, S, T \) in order. The segment addition postulate states that if three points are collinear, the sum of the lengths of the two smaller segments equals the length of the larger segment.
Step 1: Equation with \( P, Q, R \)
If \( Q \) is between \( P \) and \( R \), then \( PQ + QR = PR \).
Step 2: Equation with \( Q, R, S \)
If \( R \) is between \( Q \) and \( S \), then \( QR + RS = QS \).
Step 3: Equation with \( R, S, T \)
If \( S \) is between \( R \) and \( T \), then \( RS + ST = RT \).
Problem 4: Proof (Midpoint and Congruence)
Given: \( X \) is the midpoint of \( \overline{WY} \), \( \overline{WX} \cong \overline{XZ} \)
Prove: \( \overline{XY} \cong \overline{XZ} \)
| Statements | Reasons |
|---|---|
| 2. \( WX = XY \) | 2. Definition of midpoint (a midpoint divides a segment into two equal parts) |
| 3. \( \overline{WX} \cong \overline{XZ} \) | 3. Given |
| 4. \( WX = XZ \) | 4. Definition of congruent segments (congruent segments have equal length) |
| 5. \( XY = XZ \) | 5. Substitution Property (replace \( WX \) with \( XY \) from Step 2) |
| 6. \( \overline{XY} \cong \overline{XZ} \) | 6. Definition of congruent segments (if lengths are equal, segments are congruent) |
Problem 5: Proof (Congruent Segments)
Given: \( \overline{AB} \cong \overline{CD} \)
Prove: \( \overline{AC} \cong \overline{BD} \)
| Statements | Reasons |
|---|---|
| 2. \( AB = CD \) | 2. Definition of congruent segments |
| 3. \( AC + CD = AD \) | 3. Segment Addition Postulate ( \( C \) is between \( A \) and \( D \), so \( AC + CD = AD \)) |
| 4. \( AB + BD = AD \) | 4. Segment Addition Postulate ( \( B \) is between \( A \) and \( D \), so \( AB + BD = AD \)) |
| 5. \( CD + BD = AD \) | 5. Substitution Property (replace \( AB \) with \( CD \) from Step 2) |
| 6. \( AC + CD = CD + BD \) | 6. Transitive Property (both equal \( AD \), so they equal each other) |
| 7. \( AC = BD \) | 7. Subtraction Property (subtract \( CD \) from both sides) |
| 8. \( \overline{AC} \cong \overline{BD} \) | 8. Definition of congruent segments |
Final Answers (Key Equations/Proof Steps)
- \( PQ + QR = PR \)
- \( QR + RS = QS \)
- \( RS + ST = RT \)
(For Proofs 4 and 5, the completed tables above show the full reasoning.)