multiple choice
which of the following best describes net force?
select all that apply.
a it is equal to the difference between the two opposing forces acting on an object.
b a nonmoving object has a net force of zero, and a moving object has a net force greater than zero.
c a nonmoving object has a net force greater than zero and a moving object has a net force equal to zero.
d it is equal to the sum of the two opposing forces acting on an object.

Question

multiple choice
which of the following best describes net force?
select all that apply.
a  it is equal to the difference between the two opposing forces acting on an object.
b  a nonmoving object has a net force of zero, and a moving object has a net force greater than zero.
c  a nonmoving object has a net force greater than zero and a moving object has a net force equal to zero.
d  it is equal to the sum of the two opposing forces acting on an object.

Accepted Answer

# Brief Explanations:
- Option A: When two forces act in opposite directions, the net force is the difference between them (e.g., if one force is $ F_1 $ and the other is $ F_2 $ in the opposite direction, net force $ F_{net}=|F_1 - F_2| $ if we consider magnitudes and directions properly). So this is correct.
- Option B: A non - moving object (in equilibrium) has a net force of zero. A moving object with constant velocity also has a net force of zero (Newton's first law). But a moving object with acceleration has a net force greater than zero. However, the option says "a moving object has a net force greater than zero", which is not always true, but the first part about non - moving objects is correct. Wait, no, actually, the statement in B is partially correct in the sense that if an object is moving with acceleration, net force is non - zero, but if moving with constant velocity, net force is zero. But the option's wording is a bit misleading, but let's re - evaluate. Wait, no, the key is about net force definition. Wait, no, let's check the other options.
- Option C: This is incorrect. A non - moving object (in static equilibrium) has net force zero, and a moving object with constant velocity also has net force zero. So C is wrong.
- Option D: When forces are opposite, they are vectors, so if we take direction into account, the net force is the sum (as vectors). For example, if one force is $ +F $ and the other is $ -F' $ (opposite direction), the net force is $ F+(-F')=F - F' $, which is the difference in magnitudes if we consider direction. Wait, actually, the net force is the vector sum of all forces. So if two forces are opposing (like one to the right and one to the left), the net force is $ F_1+F_2 $ (where $ F_2 $ is negative if we take $ F_1 $ as positive). So the magnitude would be $ |F_1 - F_2| $, but the vector sum is $ F_1+F_2 $. So option A: "difference between two opposing forces" (in magnitude, if we consider direction, it's the sum of vectors which can be a difference in magnitude). Option D: "sum of two opposing forces" (as vectors, which is correct). Wait, maybe I made a mistake earlier. Let's recall: Net force is the vector sum of all forces acting on an object. If two forces are opposing (e.g., $ F_1 $ and $ F_2 $ with $ F_2=-F_1' $ in direction), then $ F_{net}=F_1 + F_2=F_1 - F_1' $ (in terms of magnitude, it's the difference if we consider the absolute values, but as a vector sum, it's the sum). So option A: "difference between the two opposing forces" (magnitude - wise, if we consider direction, the vector sum is the sum, but the magnitude is the difference). Option D: "sum of the two opposing forces" (vector sum, which is correct). And option B: The first part "A nonmoving object has a net force of zero" is correct. The second part "a moving object has a net force greater than zero" is not always correct, but maybe the question is considering the general case where if an object is moving (changing velocity), but no, the question is about describing net force. Wait, maybe the correct options are A and D? Wait, no, let's re - define net force. Net force is the vector sum of all forces acting on an object. For two opposing forces (let's say along a straight line), $ F_{net}=F_1+F_2 $. If $ F_1 $ and $ F_2 $ are in opposite directions, say $ F_1 = 5N $ to the right and $ F_2 = 3N $ to the left, then $ F_{net}=5N+( - 3N)=2N $ to the right. The magnitude is $ 5 - 3 = 2N $, so the net force can be described as the difference in magnitude (option A) or the sum of the vector forces (option D). And option B: A non - moving object (at rest) has net force zero (correct). A moving object: if it's moving with constant velocity, net force is zero; if accelerating, net force is non - zero. But the option says "a moving object has a net force greater than zero", which is not always true, but maybe the question is considering the case where the object is in motion with a change in velocity, but the first part is correct. Wait, this is confusing. Wait, maybe the correct options are A and D. Wait, no, let's check standard definitions. Net force: the vector sum of all forces acting on an object. For two opposing forces, the net force is the sum (as vectors) which is equivalent to the difference in magnitude (if we take direction into account). So option A: "It is equal to the difference between the two opposing forces acting on an object" (correct, in terms of magnitude when forces are opposite). Option D: "It is equal to the sum of the two opposing forces acting on an object" (correct, as a vector sum). Option B: The statement "A nonmoving object has a net force of zero" is correct, but "a moving object has a net force greater than zero" is incorrect (since a moving object with constant velocity has net force zero). But maybe the question is considering that a moving object (in the sense of having motion, not necessarily constant velocity) - but no, Newton's first law says that an object in motion with constant velocity has net force zero. So option B is incorrect. Option C is incorrect. So the correct options are A and D? Wait, no, maybe I messed up. Wait, let's take an example: two forces, 10N right and 7N left. Net force is 10 - 7 = 3N right (difference, option A) and also 10+(- 7)=3N (sum, option D). So both A and D are correct. And option B: A non - moving object has net force zero (correct), but a moving object: if it's moving with constant speed in a straight line, net force is zero. So the statement "a moving object has a net force greater than zero" is false. So B is incorrect. C is incorrect. So the correct options are A and D.
# Answer:
A. It is equal to the difference between the two opposing forces acting on an object.
D. It is equal to the sum of the two opposing forces acting on an object.

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Answer: