Question

multiple choice: turn left with turtle
1 moveforward();
2 turnleft();
3 turnleft();
4 turnleft();
5 moveforward();
6 turnleft();
7 turnleft();
8 turnleft();
where will the turtle be pointing after this program is run?
hint: the turtle is pointing up at the start

Explanation:

Step1: Calculate total left - turn degrees

Each turnLeft() is a \(90^{\circ}\) turn. There are \(3 + 3=6\) turnLeft() calls. The total degrees of left - turns is \(6\times90^{\circ}=540^{\circ}\). Since a full - circle is \(360^{\circ}\), \(540^{\circ}-360^{\circ} = 180^{\circ}\) of net left - turn from the starting direction.

Step2: Determine the final direction

The turtle starts pointing 'up'. A \(180^{\circ}\) left - turn from 'up' makes the turtle point 'down'. But let's check another way.
Let's assume the starting direction is \(0^{\circ}\) (up). Each turnLeft() adds \(90^{\circ}\).
After the first three turnLeft() (lines 2 - 4): direction \(=0 + 3\times90=270^{\circ}\) (down). Then after moving forward (line 5), then three more turnLeft() (lines 6 - 8): \(270+3\times90=270 + 270=540^{\circ}\). \(540\bmod{360}=180^{\circ}\) (down). But if we consider the fact that in some turtle - graphics interpretations (assuming standard 4 - direction model: up, left, down, right with \(90^{\circ}\) increments).
Another approach:
Let's use a list of directions. Let the directions be represented as a list \(\text{directions}=[\text{'up'}, \text{'left'}, \text{'down'}, \text{'right'}]\).
Starting at index \(0\) ('up'). Each turnLeft() moves the index by \(1\) (mod \(4\)).
For the first three turnLeft(): index \(0+3 = 3\) (after mod \(4\)) (direction is 'left'). Then after moving forward, then three more turnLeft(): index \(3 + 3=6\), \(6\bmod{4}=2\) (direction is 'down').

Answer:

A. Option Text