Question

the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your answer. which of the following shows \\(\frac{16}{12}\\) as a mixed number and \\(1\frac{5}{8}\\) as an improper fraction? \\(\frac{16}{12} = \frac{4}{3}\\) and \\(1\frac{5}{8} = \frac{15}{8}\\) \\(\frac{16}{12} = 1\frac{4}{12}\\) and \\(1\frac{5}{8} = \frac{6}{8}\\) \\(\frac{16}{12} = 1\frac{1}{3}\\) and \\(1\frac{5}{8} = \frac{13}{8}\\) \\(\frac{16}{12} = \frac{8}{6}\\) and \\(1\frac{5}{8} = 1\frac{8}{5}\\)

Explanation:

Step1: Convertir $\frac{16}{12}$ a número mixto

Dividir el numerador (16) entre el denominador (12). 12 entra en 16 una vez, con un residuo de 4. Entonces, $\frac{16}{12} = 1\frac{4}{12}$, pero simplificando $\frac{4}{12}$ a $\frac{1}{3}$, queda $1\frac{1}{3}$.

Step2: Convertir $1\frac{5}{8}$ a fracción impropia

Multiplicar el entero (1) por el denominador (8) y sumar el numerador (5): $1\times8 + 5 = 13$. Entonces, $1\frac{5}{8} = \frac{13}{8}$.

Answer:

$\frac{16}{12} = 1\frac{1}{3}$ and $1\frac{5}{8} = \frac{13}{8}$ (la tercera opción, por ejemplo, si las opciones están numeradas como la tercera con $\frac{16}{12} = 1\frac{1}{3}$ and $1\frac{5}{8} = \frac{13}{8}$)