Question

mild (1 point)

1. 8x = 48
2. a - 24 = 18
3. 15y = 60
4. 4x - 20 = -44
5. x + 8 = -5

Explanation:

Problem 1: \(8x = 48\)

Step1: Isolate \(x\) by dividing both sides by 8.

To solve for \(x\) in the equation \(8x = 48\), we use the division property of equality. Divide both sides of the equation by 8:
\(\frac{8x}{8}=\frac{48}{8}\)

Step2: Simplify both sides.

Simplifying the left side, \(\frac{8x}{8}\) simplifies to \(x\). Simplifying the right side, \(\frac{48}{8} = 6\). So we get \(x = 6\).

Step1: Isolate \(a\) by adding 24 to both sides.

To solve for \(a\) in the equation \(a - 24 = 18\), we use the addition property of equality. Add 24 to both sides of the equation:
\(a - 24 + 24=18 + 24\)

Step2: Simplify both sides.

Simplifying the left side, \(-24 + 24 = 0\), so we are left with \(a\). Simplifying the right side, \(18+24 = 42\). So we get \(a = 42\).

Step1: Isolate \(y\) by dividing both sides by 15.

To solve for \(y\) in the equation \(15y = 60\), we use the division property of equality. Divide both sides of the equation by 15:
\(\frac{15y}{15}=\frac{60}{15}\)

Step2: Simplify both sides.

Simplifying the left side, \(\frac{15y}{15}\) simplifies to \(y\). Simplifying the right side, \(\frac{60}{15}=4\). So we get \(y = 4\).

Answer:

\(x = 6\)

Problem 2: \(a - 24 = 18\)