Question

y = -\frac{2}{7}x + 3
x | y
-7 | \square
0 | \square
7 | \square

Explanation:

Step1: Substitute \( x = -7 \) into the equation \( y = -\frac{2}{7}x + 3 \)

\( y = -\frac{2}{7} \times (-7) + 3 \)
\( y = 2 + 3 = 5 \)

Step2: Substitute \( x = 0 \) into the equation \( y = -\frac{2}{7}x + 3 \)

\( y = -\frac{2}{7} \times 0 + 3 \)
\( y = 0 + 3 = 3 \)

Step3: Substitute \( x = 7 \) into the equation \( y = -\frac{2}{7}x + 3 \)

\( y = -\frac{2}{7} \times 7 + 3 \)
\( y = -2 + 3 = 1 \)

Answer:

When \( x = -7 \), \( y = 5 \); when \( x = 0 \), \( y = 3 \); when \( x = 7 \), \( y = 1 \)

So the completed table is:

\( x \)	\( y \)
0	3
7	1