Question

solve for g.
$-\frac{1}{2}g + \frac{1}{4} - 2g = -2 - \frac{5}{8}g + 1$
$g = square$

Explanation:

Step1: Combine like terms on both sides

Left side: $-\frac{1}{2}g - 2g+\frac{1}{4}=-\frac{1}{2}g-\frac{4}{2}g+\frac{1}{4}=-\frac{5}{2}g+\frac{1}{4}$
Right side: $-2 + 1-\frac{5}{8}g=-1-\frac{5}{8}g$

Step2: Multiply all terms by 8 to eliminate denominators

$8\times(-\frac{5}{2}g)+8\times\frac{1}{4}=8\times(-1)-8\times\frac{5}{8}g$
$-20g + 2=-8 - 5g$

Step3: Move all g terms to left and constants to right

$-20g + 5g=-8 - 2$
$-15g=-10$

Step4: Solve for g

$g=\frac{-10}{-15}=\frac{2}{3}$

Answer:

$\frac{2}{3}$