Question

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simplify.
$(-729)^{\frac{1}{3}}$

Explanation:

Step1: Recognize root form

A fractional exponent $\frac{1}{3}$ means cube root: $(-729)^{\frac{1}{3}} = \sqrt[3]{-729}$

Step2: Find cube root of -729

Identify integer $x$ where $x^3 = -729$. Since $9^3=729$, $(-9)^3=-729$.

Answer:

$-9$