Question

1. \\(\frac{4v^2 + 20v}{v + 5}\\)

Explanation:

Step1: Factor the numerator

Factor out the greatest common factor from the numerator \(4v^{2}+20v\). The GCF of \(4v^{2}\) and \(20v\) is \(4v\), so we get \(4v(v + 5)\). Now the expression becomes \(\frac{4v(v + 5)}{v + 5}\).

Step2: Cancel common factors

We can cancel out the common factor \((v + 5)\) from the numerator and the denominator (assuming \(v
eq - 5\) to avoid division by zero). After canceling, we are left with \(4v\).

Answer:

\(4v\) (for \(v
eq - 5\))