Question

1. $49 \div 7 = $
2. $39 \div 3$
3. $66 \div 6 = $
4. $75 \div 5$

Explanation:

Problem 3: \( 49 \div 7 \)

Step 1: Recall multiplication table

We know that \( 7 \times 7 = 49 \).

Step 2: Apply division definition

Since division is the inverse of multiplication, if \( 7 \times 7 = 49 \), then \( 49 \div 7 = 7 \).

Step 1: Split the dividend

Split \( 39 \) into \( 30 + 9 \).

Step 2: Divide each part

Divide \( 30 \) by \( 3 \): \( 30 \div 3 = 10 \). Divide \( 9 \) by \( 3 \): \( 9 \div 3 = 3 \).

Step 3: Add the results

Add the two quotients: \( 10 + 3 = 13 \).

Step 1: Split the dividend

Split \( 66 \) into \( 60 + 6 \).

Step 2: Divide each part

Divide \( 60 \) by \( 6 \): \( 60 \div 6 = 10 \). Divide \( 6 \) by \( 6 \): \( 6 \div 6 = 1 \).

Step 3: Add the results

Add the two quotients: \( 10 + 1 = 11 \).

Answer:

\( 7 \)

Problem 4: \( 39 \div 3 \)