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23. \\(\\dfrac{4p^4 - 17p^2 + 14p - 3}{2p - 3}\\)

Question

  1. \\(\dfrac{4p^4 - 17p^2 + 14p - 3}{2p - 3}\\)

Explanation:

Step1: Divide the leading term

Divide the leading term of the numerator \(4p^4\) by the leading term of the denominator \(2p\) to get \(2p^3\). Multiply the denominator \(2p - 3\) by \(2p^3\) to get \(4p^4 - 6p^3\). Subtract this from the numerator:

$$ LATEXBLOCK0 $$

Step2: Divide the new leading term

Divide the leading term \(6p^3\) by \(2p\) to get \(3p^2\). Multiply the denominator by \(3p^2\) to get \(6p^3 - 9p^2\). Subtract this from the previous result:

$$ LATEXBLOCK1 $$

Step3: Divide the new leading term

Divide the leading term \(-8p^2\) by \(2p\) to get \(-4p\). Multiply the denominator by \(-4p\) to get \(-8p^2 + 12p\). Subtract this from the previous result:

$$ LATEXBLOCK2 $$

Step4: Divide the new leading term

Divide the leading term \(2p\) by \(2p\) to get \(1\). Multiply the denominator by \(1\) to get \(2p - 3\). Subtract this from the previous result:

$$ LATEXBLOCK3 $$

Step5: Combine the results

The quotient is the sum of the terms we found: \(2p^3 + 3p^2 - 4p + 1\) and the remainder is \(0\).

Answer:

\(2p^3 + 3p^2 - 4p + 1\)