Question

1. \\(\frac{b^2 + 9b + 20}{b + 4}\\)

Explanation:

Step1: Factor the numerator

We factor the quadratic expression \(b^2 + 9b + 20\). We need two numbers that multiply to \(20\) and add up to \(9\). Those numbers are \(4\) and \(5\). So, \(b^2 + 9b + 20=(b + 4)(b + 5)\).

Step2: Simplify the fraction

Now we have \(\frac{(b + 4)(b + 5)}{b + 4}\). Since \(b
eq - 4\) (to avoid division by zero), we can cancel out the common factor \((b + 4)\) from the numerator and the denominator.
After canceling, we are left with \(b + 5\).

Answer:

\(b + 5\) (for \(b
eq - 4\))