Question

math focus

1. identify when the voltage doubles, what happens to the current?

Explanation:

Step1: Recall Ohm's Law

Ohm's Law is \(I=\frac{V}{R}\), where \(I\) is current, \(V\) is voltage, and \(R\) is resistance (assumed constant here).

Step2: Analyze when voltage doubles

Let the initial voltage be \(V_1\) and current be \(I_1=\frac{V_1}{R}\). When voltage doubles, \(V_2 = 2V_1\). Then \(I_2=\frac{V_2}{R}=\frac{2V_1}{R}\).
Since \(I_1=\frac{V_1}{R}\), we have \(I_2 = 2I_1\).

Answer:

The current also doubles.