Question

luca is in a culvert below street level. he launches an object at an upward velocity of 40 feet per second. use geogebra to graph the situation using the formula y = -16t² + 40t - 5. how far above or below street level is lucas initial launching point? (1 point)
o 5 feet above
o 0 feet above or below
o 2.5 feet below
o 5 feet below

Explanation:

Step1: Analyze the formula for initial position

The general formula for vertical motion is \(y = - 16t^{2}+v_{0}t + y_{0}\), where \(y_{0}\) is the initial height. In the given formula \(y=-16t^{2}+40t - 5\), when \(t = 0\) (initial time), \(y=y_{0}\).

Step2: Calculate the initial position

Substitute \(t = 0\) into the formula \(y=-16t^{2}+40t - 5\). Then \(y=-16\times0^{2}+40\times0 - 5=- 5\).

Answer:

5 feet below