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Question
the length of the hypotenuse, line segment ac, in right triangle abc is 25 cm. the length of line segment bc is 15 cm. which is the approximate measure of angle acb? 31.0° 36.9° 53.1° 59.0°
Step1: Identify triangle parts
In right triangle \(ABC\), hypotenuse \(AC = 25\) cm, \(BC = 15\) cm. Let \(\angle ACB=\theta\). We use cosine: \(\cos\theta=\frac{BC}{AC}\).
Step2: Calculate cosine value
Substitute values: \(\cos\theta=\frac{15}{25}=0.6\).
Step3: Find angle
\(\theta=\arccos(0.6)\approx53.1^\circ\).
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53.1° (corresponding to the option with 53.1°)