Question

a layer of copper welded to the bottom of a skillet weighs 125 g. how much of heat is needed to raise the temperature of the copper layer from 25 °c to 300 °c? the specific heat capacity (c) of cu is 0.387 j/(g·k)

Explanation:

Step1: Determine temperature change

The change in temperature $\Delta T$ in Kelvin is the same as in Celsius. $\Delta T=T_2 - T_1$. So, $\Delta T=(300 - 25)\text{ K}= 275\text{ K}$.

Step2: Use heat - transfer formula

The formula for heat transfer is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. Given $m = 125\text{ g}$, $c=0.387\text{ J/(g}\cdot\text{K)}$, and $\Delta T = 275\text{ K}$. Then $Q=125\times0.387\times275$.
$Q = 125\times0.387\times275=13359.375\text{ J}$

Answer:

$13359.375\text{ J}$