Question

laurel has $71.
which set of bills could laurel have?
choose 1 answer:
a 3 twenty dollar bills, 1 ten dollar bill, and 1 one dollar bill
b 4 ten dollar bills, 4 five dollar bills, and 1 one dollar bill
c 7 ten dollar bills and 1 five dollar bill

Explanation:

Step1: Calculate total for Option A

3 twenty - dollar bills: \(3\times20 = 60\), 1 ten - dollar bill: \(1\times10 = 10\), 1 one - dollar bill: \(1\times1 = 1\). Total: \(60 + 10+1=71\).

Step2: Calculate total for Option B

4 ten - dollar bills: \(4\times10 = 40\), 4 five - dollar bills: \(4\times5 = 20\), 1 one - dollar bill: \(1\times1 = 1\). Total: \(40 + 20+1 = 61
eq71\).

Step3: Calculate total for Option C

7 ten - dollar bills: \(7\times10 = 70\), 1 five - dollar bill: \(1\times5 = 5\). Total: \(70 + 5=75
eq71\).

Answer:

A. 3 twenty dollar bills, 1 ten dollar bill, and 1 one dollar bill