Question

a 0.2 kg squirrel jumps from a tree. at 0.3 s, the squirrel is 1.25 m above the ground. what is the potential energy of the squirrel?
ep = ? j
ep = mgh
for gravitational acceleration, use g = 10 m/s².
2.5 j
0 j
3.2 j

Explanation:

Step1: Identify the formula

The formula for gravitational potential energy is \(E_p = mgh\), where \(m\) is mass, \(g\) is gravitational acceleration, and \(h\) is height.

Step2: Substitute the values

Given \(m = 0.2\space kg\), \(g = 10\space m/s^2\), and \(h = 1.25\space m\). Substitute these into the formula: \(E_p=(0.2)(10)(1.25)\).

Step3: Calculate the result

\((0.2)(10)(1.25)=2\times1.25 = 2.5\).

Answer:

\(2.5\space J\)