Question

a 3.5 kg object being pushed by a force of 10 n across the floor. what is the acceleration of the object?

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is the force, \(m\) is the mass, and \(a\) is the acceleration. We need to solve for \(a\), so we can rewrite the formula as \(a=\frac{F}{m}\).

Step2: Substitute the given values

We are given that \(F = 10\space N\) and \(m=3.5\space kg\). Substituting these into the formula \(a=\frac{F}{m}\), we get \(a=\frac{10}{3.5}\space m/s^{2}\).

Step3: Calculate the value

\(a=\frac{10}{3.5}\approx 2.86\space m/s^{2}\)

Answer:

The acceleration of the object is approximately \(2.86\space m/s^{2}\)