Question

a 6.2 kg bowling ball that weighs 60.76 n is accelerating at 1.8 m/s². after 2 seconds, it reaches a speed of 3.6 m/s. what is its momentum at this point?

a. 16.9 kg·m/s

b. 1.7 kg·m/s

c. 11.2 kg·m/s

d. 22.3 kg·m/s

Explanation:

Step1: Recall momentum formula

Momentum \( p \) is calculated by the formula \( p = mv \), where \( m \) is mass and \( v \) is velocity.

Step2: Identify values

The mass \( m \) of the bowling ball is \( 6.2 \, \text{kg} \) and the velocity \( v \) at the point is \( 3.6 \, \text{m/s} \).

Step3: Calculate momentum

Substitute \( m = 6.2 \, \text{kg} \) and \( v = 3.6 \, \text{m/s} \) into the formula:
\( p = 6.2 \times 3.6 \)
\( p = 22.32 \, \text{kg·m/s} \) (approximately \( 22.3 \, \text{kg·m/s} \))

Answer:

D. 22.3 kg·m/s