Question

the jfet is a square-law device because of the mathematical expression of its transfer characteristic curve.
select one:
○ true
○ false

Explanation:

The transfer characteristic of a JFET (Junction Field - Effect Transistor) is given by the equation \(I_D = I_{DSS}(1 - \frac{V_{GS}}{V_{P}})^2\) (for \(V_{P}\leq V_{GS}\leq0\)), where \(I_D\) is the drain current, \(I_{DSS}\) is the drain - source current with \(V_{GS} = 0\), \(V_{GS}\) is the gate - source voltage, and \(V_{P}\) is the pinch - off voltage. Since the relationship between \(I_D\) and \(V_{GS}\) follows a square - law (a quadratic relationship), the JFET is a square - law device. So the statement is true.

Answer:

True