Question

a jet fighter takes off from a catapult on an aircraft carrier. after 2.0s, it reaches the end of the catapult with a speed of ... assuming the acceleration is constant, what is the length of the catapult?

Explanation:

Step1: Identify known quantities

We know the initial velocity \( u = 0 \, \text{m/s} \) (starts from rest), time \( t = 2.0 \, \text{s} \), and final velocity \( v = 60 \, \text{m/s} \) (assuming the speed at the end is 60 m/s, as the image might have that, common in such problems). We need to find the length of the catapult, which is the distance \( s \) traveled.

Step2: Find acceleration first

Using the equation \( v = u + at \), we can solve for \( a \).
Substituting the values: \( 60 = 0 + a \times 2.0 \)
So, \( a = \frac{60}{2.0} = 30 \, \text{m/s}^2 \)

Step3: Find distance using kinematic equation

Use the equation \( s = ut + \frac{1}{2}at^2 \)
Substitute \( u = 0 \), \( a = 30 \, \text{m/s}^2 \), \( t = 2.0 \, \text{s} \)
\( s = 0 \times 2.0 + \frac{1}{2} \times 30 \times (2.0)^2 \)
\( s = 0 + 15 \times 4.0 \)
\( s = 60 \, \text{m} \)

Answer:

The length of the catapult is \( \boldsymbol{60 \, \text{meters}} \) (assuming final speed is 60 m/s, adjust if actual speed from image differs).