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jaron scored 300 and 400 points in the first two rounds of a computer g…

Question

jaron scored 300 and 400 points in the first two rounds of a computer gaming tournament. sorren scored 250 points in the first round. he wants to get the same total score as jaron. which of these will help him find out how many points he needs to catch up? options: ((300 + 400) - 250 = p); (400 - 250 = p); (300 - 400 = p); (300 + 400 + 250 = p)

Explanation:

Step1: Understand the problem

Jirot has 300 and 400 points in two rounds, and the opponent has 250 points. We need to find the formula to compare Jirot's total points with the opponent's to see if he catches up. Jirot's total points are \(300 + 400\), and we compare it with the opponent's 250 plus the points \(p\) the opponent needs to catch up. So the equation should be \(300 + 400=250 + p\). Wait, looking at the options, the first option is \((300 + 400)-250 = p\), which is equivalent to \(300 + 400=250 + p\) (by rearranging: \(p=(300 + 400)-250\)). Let's check the options:

Option 1: \((300 + 400)-250 = p\) – this calculates how many points \(p\) the opponent needs to catch up, which is what we need.

Option 2: \(300-250 = p\) – only considers one of Jirot's rounds, wrong.

Option 3: \(400-250 = p\) – only considers one of Jirot's rounds, wrong.

Option 4: \(300 + 400 + 250 = p\) – adds all, which is wrong.

So the correct formula is \((300 + 400)-250 = p\).

Answer:

\((300 + 400)-250 = p\) (the first option among the given choices)