Question

4.) an inequality is shown.
$4x + 10 < 0$
what is the solution to the inequality? (2 pts)
a. $x < -14$
b. $x < -\frac{5}{2}$
c. $x < \frac{1}{6}$
d. $x < 6$

Explanation:

Step1: Isolate the term with x

Subtract 10 from both sides of the inequality \(4x + 10 < 0\).
\(4x + 10 - 10 < 0 - 10\)
\(4x < -10\)

Step2: Solve for x

Divide both sides by 4. Since 4 is positive, the inequality sign remains the same.
\(\frac{4x}{4} < \frac{-10}{4}\)
Simplify the fractions: \(x < -\frac{5}{2}\)

Answer:

B. \(x < -\frac{5}{2}\)