Question

the image below compares waves of red and blue light.
red light
blue light
compared to the blue wave, the red wave has a frequency and a wavelength. therefore, the red wave has than the blue wave.

Explanation:

Step1: Analyze wavelength

Wavelength is the distance between two consecutive crests (or troughs). From the image, the red - light wave has a longer distance between consecutive crests compared to the blue - light wave. So, the red wave has a longer wavelength.

Step2: Use the relationship \(c = \lambda f\)

The speed of light \(c\) is a constant (\(c=\lambda f\), where \(\lambda\) is wavelength and \(f\) is frequency). Since \(c\) is constant (\(c = 3\times10^{8}\space m/s\) in vacuum), and \(\lambda_{red}>\lambda_{blue}\), from \(f=\frac{c}{\lambda}\), we can say that \(f_{red}

Step3: Analyze energy

The energy of a photon is given by \(E = hf\) (where \(h\) is Planck's constant, \(h = 6.626\times 10^{-34}\space J\cdot s\)). Since \(f_{red}

Answer:

Compared to the blue wave, the red wave has a lower frequency and a longer wavelength. Therefore, the red wave has less energy than the blue wave.