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Identify the factors to multiply
The problem asks to multiply \(3x(x - 1)\) using algebra tiles by following three steps:
- Represent the first factor, \(3x\), along the vertical axis (Factor 1).
- Represent the second factor, \(x - 1\), along the horizontal axis (Factor 2).
- Complete the grid area (Product) by dragging tiles to represent the product of these factors.
Represent the factors with tiles
Using Algebra Tiles:
- Factor 1 (vertical): \(3x\) is represented by 3 positive green/orange \(x\)-tiles stacked vertically.
- Factor 2 (horizontal): \(x - 1\) is represented by 1 positive \(x\)-tile and 1 negative unit tile (\(-1\)) placed horizontally.
Determine the product area
Using Polynomial Multiplication:
- Multiplying each vertical \(x\)-tile by the horizontal \(x\)-tile yields an \(x^2\)-tile:
Since there are 3 vertical \(x\)-tiles and 1 horizontal \(x\)-tile, we place 3 positive \(x^2\)-tiles in the first column of the product area.
- Multiplying each vertical \(x\)-tile by the horizontal \(-1\)-tile yields a \(-x\)-tile:
Since there are 3 vertical \(x\)-tiles and 1 horizontal \(-1\)-tile, we place 3 negative \(x\)-tiles in the second column of the product area.
Write the final algebraic expression
Summing the tiles in the product area:
- 3 positive \(x^2\)-tiles: \(3x^2\)
- 3 negative \(x\)-tiles: \(-3x\)
This matches the algebraic expansion:
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To complete the model for the product \(3x(x - 1)\):
- Factor 1 (Vertical Column): Place 3 positive \(x\)-tiles.
- Factor 2 (Horizontal Row): Place 1 positive \(x\)-tile and 1 negative unit tile (\(-1\)).
- Product Area:
- Place 3 positive \(x^2\)-tiles in the column under the horizontal \(x\)-tile.
- Place 3 negative \(x\)-tiles in the column under the horizontal \(-1\)-tile.
The resulting simplified product is: