Question

how much work does a supermarket checkout attendant do on a can of soup he pushes 0.330 m horizontally with a force of 4.40 n? express your answer in joules and kilocalories.
j
kcal

Explanation:

Step1: Calculate work in joules

Work formula: \(W = F\times d\). Given \(F = 4.40\space N\) and \(d=0.330\space m\).
\(W=(4.40\space N)\times(0.330\space m)\)
\(W = 1.452\space J\)

Step2: Convert joules to kilocalories

Conversion factor: \(1\space kcal=4186\space J\). Let \(x\) be the value in \(kcal\). Then \(x=\frac{W}{4186}\).
\(x=\frac{1.452\space J}{4186\space J/kcal}\approx3.47\times 10^{-4}\space kcal\)

Answer:

\(1.45\space J\) (rounded to three significant figures)
\(3.47\times 10^{-4}\space kcal\)