Question

1. how much heat must be added to 128.62 g of steam at 126.0°c to increase its temperature to 189.5°c

Explanation:

Step1: Determine the specific heat capacity of steam

The specific heat capacity of steam \(c = 2.02\space J/g^{\circ}C\)

Step2: Calculate the temperature change

\(\Delta T=T_{final}-T_{initial}\)
\(\Delta T = 189.5^{\circ}C - 126.0^{\circ}C=63.5^{\circ}C\)

Step3: Use the heat formula \(Q = mc\Delta T\)

Given \(m = 128.62\space g\), \(c = 2.02\space J/g^{\circ}C\), \(\Delta T=63.5^{\circ}C\)
\(Q=(128.62\space g)\times(2.02\space J/g^{\circ}C)\times(63.5^{\circ}C)\)
First, calculate \(128.62\times2.02 = 259.8124\)
Then, \(259.8124\times63.5 = 16508.0874\space J\approx1.65\times 10^{4}\space J\)

Answer:

\(1.65\times 10^{4}\space J\)